Thursday, 19 November 2015

limit approaches 0... x+xcosx/sinxcosx

sin(0)=0
cos(0) =1
lim(x/sin(x)) x->0 = 1 only if x is expressed in radians, but ignore that for now.
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lim((x+xcosx)/sinxcosx) x->0 should be split into two fractions
= lim((x)/sinxcosx) x->0 + lim((xcosx)/sinxcosx) x->0
You should split the first fraction into a product, and cancle the xes in the second fraction
= lim((x)/sinx) x->0 X lim((1)/cosx) x->0 + lim((x)/sinx) x->0
Now apply the formulas that I gave you.
= 1 X 1/1 +1
= 1 + 1 = 2 = Ans

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