lim 6x^2(cot x)(csc 2x) as x approaches zero

u may know cotx=cosx/sinx
and cosec2x=1/sin2x
furthur sin2x=2sinxcosx
thus coses2x=1/2sinxcosx
now putting these values in the given expression6x^2(cot x)(csc 2x)
we have

6x^2 * cosx/sinx * 1/2sinxcosx
=3x^2/(sinx)^2

now applying the limit x------>0
as u may know lim x--->0 sinx/x=1
thus in this case we have

lim x---->0 3* x/sinx * x/sinx
=3*1*1
=3
happy ot help!!and god bless u dear!!